courses | lecture materials from Practical Deep Learning | Chat library

If you look at React without JSX, you'll see that the XML-inspired syntax () is just short for React.createElement('MockComponent').

Right now, if you renamed mockComponent to MockComponent and tried using the angle bracket syntax, the first issue is that your function receives two arguments. React components are either class components that take one constructor argument (props) or functional components that take one argument (again, props). The second issue is that your function returns a React functional component, when it needs to return a rendered React element.

One way to fix this issue is to convert mockComponent into a React functional component and make module and propOverride props of the FC.

Use df.sort_values to sort the dataframe, and then use np.split to split the dataframe at the specified index(es):

You have to specify the URL as follows.

What I've done here is remove the borders from the table and collapsed the space for them.

I've then used more semantic elements for both table headings and your actual content with semantic class names. This included adding a new element for the elements you want at the bottom of the cell. Finally, the teacher and codes are floated left and right respectively.

I am not much familiar with Jinja, so this answer might not be the most efficient one.

By using basic hard coding in your Template.HTML file, I was able to achieve the results you are trying to. For this, I used the same code that was given by D-E-N in your previous question.

I combined all the attributes of your object into a string

• An attribute is differentiated from another with @ (like Course and Teacher)
• Instead of using space character, I used a _ character to represent space character in the attributes.
• If one slot contains multiple objects, they are differentiated with space character (just like in the code provided by D-E-N)

Here's the updated code of yours with these changes,

How about trying Target as shown below

Target : constant Interfaces.C.Char_Ptr := Interfaces.C.To_C ("amd");

You cannot directly loop over an IGrouping (if you are building an IQueryable of course), the documentation explains that:

Furthermore, IGrouping implements IEnumerable, which means you can compose over it using any LINQ operator after the grouping. Since no database structure can represent an IGrouping, GroupBy operators have no translation in most cases. When an aggregate operator is applied to each group, which returns a scalar, it can be translated to SQL GROUP BY in relational databases.

There are many ways to generate such a layout with dynamic data, and generally for python I'd either recommend you use excel, or use a web-based layout, and then use that to generate your output pdf.

Using HTML Manipulation

If we are talking about the web-based layout, you would need to use beautifulsoup, and the approach you would have would look like this:

1. Create a standard layout with the cells having unique ids for each position (You could use something similar to your last example).

2. Loop through your bigger containers which might need to be split, you can use beautifulsoup with an if condition to add different html depending if you need to split the data or not, e.g.:

If your lab rooms are different from your normal rooms then you should be solving lab and normal courses separately.

If you want a course to always use the same room than you don't need to encode the room twice just use a bit mask for the multiple slots that the course will take up.

[Course Id][Room Id][Slot Bit Mask]

[Course Id] is a byte 1-255

[Room Id] is a byte, assuming less than 256 rooms

[Slot Bit Mask] is a UInt32 bit mask, gives you 32 slots but you only need to use 25 (5 days * 5 slots/day)

[Course Id] and [Room Id] correspond to your separate lists of Normal and Lab, Courses and Rooms.

[Slot Bit Mask] for Normal Courses is constrained to 2^n (n = 0-24) BitwiseOr 2^m (m = 0-24), where Floor(n / 5) != Floor(m / 5). This equates to 2 unique days a week, 1 slot per day.

[Slot Bit Mask] for Lab Courses is constrained to 3 * 2^n (n = 0-3, 5-8, 10-13, 15-18, 20-23), where Floor(n / 5) != Floor(m / 5). This equates to 1 day per week, 2 consecutive slots per day. edit only need 1 lab day

Your fitness function is just the error score. An Error is when [Room Id A] == [Room Id B] AND ([Slot Bit Mask A] BitwiseAnd [Slot Bit Mask B]) > 0. Fitness = (Total - Error) / Total.

EDIT Example encoding:

Course Id = 1, Room Id = 2, Normal Course Slots = Monday 3rd slot and Friday the 4th slot. Monday 3rd slot (2^n, n = 2). Friday 4th slot (2^m, m = 23). Floor(n / 5) = 0 and Floor(m / 5) = 4, since 0 and 4 are not equal its a valid Normal Course Slot Bit Mask.

Slot Bit Mask UInt32 Bit Index 31 to Bit Index 0

(ZZZZZZZ5 43215432 15432154 32154321)

(0000000F FFFFTTTT TWWWWWTT TTTMMMMM)

Full encoding Course, Room, Slot

00000001b 00000010b 00000000 10000000 00000000 00000100b